In the trapezoid base = 6; 12 cm. And height = half the sum of the bases. Find the area of the trapezoid.

Let us draw the height of the CH trapezoid, the length of which, by condition, is equal to the half-sum of the lengths of the bases, then CH = (BC + AD) / 2 = (6 + 12) / 2 = 18/2 = 9 cm.

Determine the area of the trapezoid.

Savsd = (ВС + АD) * СН / 2 = (6 + 12) * 9/2 = 18 * 9/2 = 81 cm2.

Answer: The area of the trapezoid is 81 cm2.



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