In the triangle ABC AB = BC = 5, AC = 6, a circle with center O is inscribed in it. Find the area of the triangle.

Let’s build the height of the ВН, which will also be the median of the triangle. Then AH = CH = AC / 2 = 6/2 = 3 cm.

In a right-angled triangle ABН, according to the Pythagorean theorem: BH ^ 2 = AB ^ 2 – AH ^ 2 = 25 – 9 = 16.

BH = 4 cm.

Then Savs = ВН * AC / 2 = 4 * 6/2 = 12 cm2.

Answer: The area of the triangle is 12 cm2.



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