In the triangle ABC, AB = BC, AM is the median, AB + BM = 9, MC + AC = 7. Find the sides of a triangle

Since AM is the median of the triangle, then BM = CM.

AB + BM = 9 cm.

MС + AC = 7 cm.

Let’s add two equations.

AB + BM + MС + AC = 16.

AB = BC, BM + MС = BC, then:

AB + BC + AC = 2 * AB + AC = 16 cm.

AC = 7 – BC = 7 – (BC / 2) = 7 – (AB) / 2.

Then, 2 * AB + 7 – (AB / 2) = 16 cm.

3 * AB / 2 = 16 – 7 = 9 cm.

3 * AB = 18.

AB = 18/3 = 6 cm.

BC = AB = 6 cm.

MС = 6/2 = 3 cm.

AC = 7 – 3 = 4cm.

Answer: The sides of the triangle are 6 cm, 6 cm, 4 cm.



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