In the triangle ABC AB = BC, and the height AH divides the side BC into segments BH = 40 and CH = 40. Find cosB.

Since the height AH divides the opposite side of BC into equal parts, then AB = AC, but AB = BC. Therefore, triangle ABC is equilateral.

In an equilateral triangle, all angles are equal, and since the sum of the angles in a triangle is 180 º, then all angles are equal to 60 º.

cos B = cos 60 º = 1/2.



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