In the triangle ABC AB = BC, the outer angle at the vertex A is 158 °. Find angle B.

1. Let’s calculate what is the inner angle of the triangle at the vertex A.

180 – 158 = 22 °.

2. Since the condition of the problem the triangle is an isosceles angle C = angle A = 22 °.

3. Determine the degree measure of the angle B.

180 – 22 * 2 = 136 °.

Answer: Angle B is 136 degrees.



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