In the triangle ABC AC = BC = 10, AB = 16, find cos A.
| April 11, 2021 | education
According to the condition of the assignment, the AC side of the triangle is equal to the BC side, that is, this triangle will be isosceles.
Let’s mentally draw the height to the AB side. From the school curriculum in geometry, we know that in this type of triangles it will also be the median.
Let us determine what half of the AB side will be equal to, when from the condition of the task we know that it is 16 conventional units:
16: 2 = 8.
We find out what the cosine of angle A will be equal to:
8: 10 = 0.8.
Answer: It is equal to 0.8.
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