In the triangle ABC AC = BC = 38, the angle C is 30 °. Find the height AH.

Since the 2 sides of the triangle are equal to each other, then the triangle is isosceles, therefore the angles at the base are equal to each other, then:

CAB + CBA = (180 – ACB) / 2 = (180 -30) / 2 = 75 degrees.

Altitude AH = BC * sin (CBA) = 38 * sin (75) = 38 * 0.96589 = 36.7.



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