In the triangle ABC AC = BC = 6, height AH = 3. find the degree measure of the angle C.

In a right-angled triangle АСН CosАСН = СН / АС = 3/6 = 1/2.

Angle ACH = arcos (1/2) = 60.

Since AC = BC, the triangle ABC is isosceles, and then the height of CH is also the bisector of the angle ACB. Then the angle ACB = 2 * ACH = 2 * 60 = 120.

Answer: Angle ACB is 120.



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