In the triangle ABC AC = BC, the height of CP is 26, cosA = √ (2) / 2. Find AB.

According to the condition of the problem, this triangle ABC is isosceles (AC = BC), the height of CP is the median.
The cosine value √2 / 2 is a tabular value that corresponds to an angle of 45 °.
Angle A at the base of an isosceles triangle is 45 °.
The right-angled triangle APC is isosceles, AP = CP = 26.
Find AB:
AB = 2 * AP = 52.
Answer: base AB is 26.



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