In the triangle ABC, it is known that AB = 4, AC = 7 and BC = √93. Find the radius of the circle circumscribed

In the triangle ABC, it is known that AB = 4, AC = 7 and BC = √93. Find the radius of the circle circumscribed about this triangle.

By the cosine theorem, we determine the value of the angle BAC.

BC ^ 2 = AB ^ 2 + AC ^ 2 – 2 * AB * AC * CosA.

93 = 16 + 49 – 2 * 4 * 7 * CosA.

56 * CosA = -28.

CosA = -1 / 2.

Angle BAC = 120.

Determine the radius of the circle circumscribed around the triangle.

R = (√93 / 2 * Sin120) = (√93 / (2 * √3 / 2) = √31

R = √31 cm.

Answer: The radius of the circumscribed circle is √31 cm.



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