In the triangle ABC, it is known that AB = 7, BC = 3 √3, sine A = 3 √3 divided by 14. Find the angle C.

univerkov | July 15, 2021 | education

Let’s apply the sine theorem.

BC / SinA = AB / SinC.

SinC = AB * SinA / BC = 7 * (3 * √3 / 14) / 3 * √3 = 7/14 = 1/2.

Angle C = arcsin (1/2) = 30.

Answer: Angle C is 30.

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