In the triangle ABC, the angle C of the straight line AC = 9 cos the angle A = 0.3 find AB.

1) triangle ABC, ∡ с – straight line.

ac = 9;

cos a = 0.3;

2) cos a = ac / ab;

ac – adjacent leg.

ab is the hypotenuse.

3) Let us express ab.

ab * cos a = ac;

ab = ac / ab;

4) Find ab.

ab = 9 / 0.3;

Multiply the numerator and denominator by 10.

ab = 9 * 10 / (0.3 * 10);

ab = 90/3 = 30;

Answer: ab = 30.



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