In the triangle ABC, the angle is C = 65 °, AB = CB. AH is the height of the triangle. Find the corner BAH.

We are given that AB = BC, therefore the triangle ABC given to us is isosceles. In an isosceles triangle, the angles at the base are equal, so the angle C is equal to the angle A, the angle A = 65 °.

It is also known that the sum of all angles in this triangle is 180 °. Let’s find the value of the angle B, for this it is necessary to subtract the value of the other two angles from 180 °:

180 ° – 65 ° -65 ° = 50 ° is the value of the angle B.

It is known that AH is the height in the given triangle, therefore the angle BHA = 90 °;

Let’s find the value of the angle BAH, for this we need to subtract the value of the angles BHA and ABH from 180 °:

180 ° -90 ° -50 ° = 40 ° is the value of the BAH angle.