In the triangle ABC, the angle is C = 88 °, AD and BE are the bisectors. intersecting at point O. Find the angle AOB.

Let us determine the sum of the angles ABC and CAB of the triangle ABC.

Angle (ABC + CAB) = (180-88) = 92.

Since AD and BE, by condition, are the bisectors of the angles CAB and ABC, the sum of the angles OAB and OBA will be equal to: (OBA + OAB) = (ABC + CAB) / 2 = 92/2 = 46.

Then in triangle OAB the angle AOB = (180 – 46) = 134.

Answer: The value of the angle AOB is 134.



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