In the triangle ABC, the angle is C = 90, sinA = 0.75, AC = √7. Find AB.
| August 7, 2021 | education
We express the side AB through the sides and angle A of the triangle ABC:
AC / AB cos A; AB = AC / cos A;
AC = √7;
cos A = √ (1- sin 2 A) = √ (1 -0.75 2) = √ (1 – 9/16) = √7 / 2;
AB = √7 / (√7 / 2) = 2.
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