In the triangle ABC, the angle is C = 90 °. The hypotenuse AB is divided by the height CH,

In the triangle ABC, the angle is C = 90 °. The hypotenuse AB is divided by the height CH, drawn from the top of the right angle, into segments AH = 18 cm and BH = 8 cm.Find the height of the CH.

Given a right-angled triangle with a right angle C, where the vertex CH, drawn from the vertex of the right angle, divides the hypotenuse into two segments AH = 18cm and BH = 8cm. Find the height CH.
Knowing that, the height drawn from the top of the right angle is half the hypotenuse, therefore:
CH = 1 / 2AB substitute the values and solve
CH = 1/2 (18 + 8)
CH = 1/2 * 26
CH = 13
Answer: CH = 13cm