In the triangle ABC, the angle is C-straight, cos A = 3√10 \ 10. find: tg A.

Let the length of the leg AC = 3 * √10 * X cm, then the length of the hypotenuse AB = 10 * X cm.

By the Pythagorean theorem, we determine the length of the BC leg.

BC ^ 2 = AB ^ 2 – AC ^ 2 = 100 * X ^ 2 – 90 * X ^ 2 = 10 * X ^ 2.

BC = X * √10 cm.

Then tgBAC = BC / AC = X * √10 / 3 * √10 * X = 1/3.

Answer: The tangent of the angle BAC is 1/3.



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