In the triangle ABC, the angle with the straight line BC = 3 cosB = 0.6 find AD.

AB – hypotenuse, BC and AC – legs. By definition, the cosine of an acute angle of a right-angled triangle is the ratio of the adjacent leg to the hypotenuse, therefore:

cos B = BC / AB, whence AB = BC / cos B.

For our conditions, we have:

AB = 3 / 0.6 = 5.

Answer: AB = 5 units.



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