In the triangle abc, the outer angle at the vertex c is 116 degrees ab is equal to bc find the degree measure of the angle b.

The angle ACB is adjacent to the angle BCD, the sum of which is 180, then the angle ACB = (180 – BCD) = (180 – 116) = 64.

Since, by condition, AB = BC, the triangle ABC is isosceles, and then the angle BAC = ACB = 64.

The sum of the interior angles of the triangle is 180, then the angle ACB = (180 – 64 – 64) = 52.

Answer: The angle ABC is 52.



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