In the triangle ABC, the sides of the AC BC are equal, the angle C is 98 degrees. Find the outer angle at the vertex B.

In an isosceles triangle, the angles at the base are equal. Find the angle at the base:

(180 – 98): 2 = 82: 2 = 41 angle at the base;

Find the outer corner to the corner at the base. The outer corner and the corner at the base are adjacent:

180 – 410 = 139

Answer: the outer corner at the top is 139.



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