In the triangle, the sides a, b and the angle gamma between them are given.

In the triangle, the sides a, b and the angle gamma between them are given. Find the third side from this triangle a = 2√2m, b = 3m, gamma = 45 degrees.

To find the length of the BC side, we apply the cosine theorem for a triangle.

AB ^ 2 = AC ^ 2 + BC ^ 2 – 2 * AC * BC * Cos45.

AB ^ 2 = (3) ^ 2 + (2 * √2) ^ 2 – 2 * 3 * 2 * √2 * √2 / 2 = 9 + 8 – 12 = 5.

AB = √5 cm.

Answer: The length of the third side is √5 cm.



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