In the two-digit number, the numbers were reversed, and it increased 3.4 times. What is the product of these numbers?

Suppose the number consisted of the digits x and y, where x is in the tens place and y is in the ones place.

Let us decompose this number into bit terms: 10 * x + y.

Having swapped x and y, we also expand the resulting number: 10 * y + x.

It follows from the condition of the problem that:

10 * y + x = 3.4 * (10 * x + y);

Let’s simplify the expression:

10 * y + x = 34 * x + 3.4 * y;

10 * y – 3.4 * y = 34 * x – x;

6.6 * y = 33 * x;

y = 5 * x;

So, y is 5 times more than x.

Considering that both x and y are single-digit numbers, we define that x = 1; y = 1 * 5 = 5.

Other options are excluded, since for x> 1, y will be greater than 9, which is unacceptable.

Find the product 15 and 51:

15 * 51 = 765.

Answer: 765.