In the urn there are 16 white and 4 red balls, 2 balls are taken out without return, the probability that they are both white.

There are 20 balls in total.
The probability of removing the first white ball out of 4:
p1 = 4/20;
The conditional probability of taking out the second white ball, provided that the first ball was white:
p1 = 3/19;
The probability that both balls taken out are white:
P = p1 * p2 = 4/20 * 3/19 = 0.032.
Answer: 0.032.