In trapezium ABCD, the base lengths are known: AD = 15, BC = 6. the area of the triangle ACD is 60.

In trapezium ABCD, the base lengths are known: AD = 15, BC = 6. the area of the triangle ACD is 60. Find the area of the trapezoid ABCD.

From vertex C we draw the height CH, which is the height of the trapezoid and the height of the triangle ACD.

Let’s use the formula for the area of a triangle. Sasd = AD * CH / 2.

60 = 15 * CH / 2.

CH = 60 * 2/15 = 8 cm.

Then the area of the trapezoid is:

Savsd = (ВС + АD) * СН / 2 = (6 + 15) * 8/2 = 84 cm2.

Answer: Savsd = 84 cm2.



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