In trapezium ABCD, the height CH is drawn. Find the angle ACH if AH = 8√2, AC = 16

We calculate the value of ∠АСН through one of the trigonometric functions of this angle (sine).

The sine of ∠АСH is equal to the quotient of dividing the length of the segment AH – the leg of a right triangle

ACH by the length of its side AC, which is the hypotenuse of the specified triangle:

АН / АС = sinus ∠АСН.

AH: AC = 8√2: 16 = sine ∠ACH = √2 / 2.

√2 / 2 is a 45 ° sine. That is, ∠АСН = 45 °.

Answer: ∠АСН = 45 °.



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