In trapezium ABCD with bases AD and BC, diagonals are drawn. Prove that triangle ABD and DAC have equal areas.

The area of the triangle ABD is equal to: Savd = AD * BН / 2.

The area of the triangle DАС is equal to: SDAС = АD * CK / 2.

In a trapezoid, the heights drawn from obtuse angles to the base are equal, BH = CK, and the base AD of the triangles is common, then Savd = Sdas, which was required to prove.



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