In trapezoid ABCD, AB = CD, angle BDA = 64, angle BDC = 19, Find the angle ABC.

Determine the value of the angle ADC.

Angle ADC = ADB + BDC = 64 + 19 = 83.

Since, according to the condition, the lateral side AB = CD, the trapezoid ABCD is isosceles, and therefore the angle BAD = ADC = 83.

In a trapezoid, the sum of the angles at its sides is 180.

Then the angle ABC = 180 – 83 = 97.

Answer: Angle ABC = 97.



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