In trapezoid ABCD AD is a larger base, AD = 8 cm, BC = 2 cm. Through point C, a straight line
| July 14, 2021 | education
In trapezoid ABCD AD is a larger base, AD = 8 cm, BC = 2 cm. Through point C, a straight line CF is drawn, parallel to the side AB (F ∈ AD). Find the center line of the triangle CDF parallel to DF.
In the quadrangle ABCF, the sides BC and AF are parallel as the bases of a trapezoid, and the sides AB and CF are parallel by condition, then the quadrilateral is a parallelogram in which the opposite sides are equal. AF = BC = 2 cm.Then DF = AD – AF = 8 – 2 = 6 cm.
In a triangle, the midline is half the length of the base to which it is parallel. KM = DF / 2 = 6/2 = 3 cm.
Answer: The midline of the CDF triangle is 3 cm.
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