In trapezoid ABCD, angles A and B are straight. diagonal AC is the bisector of angle A and is equal to 6 cm.
In trapezoid ABCD, angles A and B are straight. diagonal AC is the bisector of angle A and is equal to 6 cm. Find the area of the trapezoid if the angle CDA is 60 degrees.
From the top of the trapezoid, we lower the height CH.
Since, by condition, AC is the bisector of a right angle, the angles ACН and СAН are equal to 450, and therefore the triangle ACН is isosceles and AH = CH.
Then, by the Pythagorean theorem, AC ^ 2 = AH ^ 2 + CH ^ 2 = 2 * AH ^ 2.
36 = 2 * AH ^ 2.
AH ^ 2 = 18.
AH = CH = BC = AB = 3 * √2 cm.
Consider a right-angled triangle СНD, in which the angle CDH = 60, and the leg СН = 3 * √2.
DH = CH / tan 60 = 3 * √2 / √3 = 3 * √2 * √3 / 3 = √6.
Then АD = AH * DH = 3 * √2 + √6
The area of the trapezoid is equal to the sum of the area of the square ABCH and the triangle CHD.
Sabch = AH ^ 2 = (3 * √2) ^ 2 = 18 cm2.
Schd = HD * CH / 2 = √6 * 3 * √2 / 2 = √3 * √2 * 3 * √2 / 2 = 3 * √3 cm2.
S = 18 + 3 * √3 cm2.
Answer: S = 18 + 3 * √3 cm2.