In trapezoid ABCD, base BC is perpendicular to side AB, angle D is 60, diagonal AC is perpendicular
In trapezoid ABCD, base BC is perpendicular to side AB, angle D is 60, diagonal AC is perpendicular to side CD equal to 8cm. Find the base length BC.
From the top of the trapezoid, we lower the height CH.
In the formed right-angled triangle СНD, angle D = 60, angle H = 90, then angle C = 180 – 90 – 60 = 30.
The DН leg lies opposite an angle of 30, and therefore is equal to half the length of the СD hypotenuse.
DН = СD / 2 = 8/2 = 4 cm.
Consider a right-angled triangle AСD, in which angle D = 60, angle C = 90, then angle A = 180 – 90-60 = 30.
The СD leg lies opposite the angle A equal to 300, therefore it is equal to half the length of the hypotenuse of blood pressure. Then AD = 2 * СD = 2 * 8 = 16 cm.
Segment AH = ADL – DН = 16 – 4 = 12 cm.
Since ABCH is a rectangle, BC = AH = 12 cm.
Answer: Base length BC = 12 cm.