In trapezoid ABCD from the vertex of angle B, a straight line is drawn parallel to side CD

In trapezoid ABCD from the vertex of angle B, a straight line is drawn parallel to side CD and intersecting side AD at point E so that angle ABE = 75. angle A = 40. What is the angle CBE?

In triangle ABE, we determine the value of the angle BEA.

BEA = 180 – 40 – 75 = 65.

Angle CBE = BEA as cross-lying angles at the intersection of parallel straight lines AD and BC secant BE.

Angle CBE = 65.

Answer: angle CBE = 65.



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