In trapezoid ABCD, point M lies on the side of AB. O- the point of intersection of the diagonal BD and the segment CM
In trapezoid ABCD, point M lies on the side of AB. O- the point of intersection of the diagonal BD and the segment CM. Find the area of the trackball BOC if BM = 2 AM, CO = 5 OM and the area of the triangle COD is 1.
Draw from point M a straight line MP parallel to the bases of the trapezoid and intersecting the diagonal BD with point E.
Triangles ВOС and MOE are similar in two angles, then OK / OH = OС / OM = 5 * X / 1 * X.
Then the length of the segment KH = 6 * X.
Let us extend the segment KH to the intersection with the base AD.
Then KН / НL = ВM / AM = 2/1.
NL = KН / 2 = 3 * X. Then KL = KН + НL = 9 * X.
Triangles BOC and ВСD have a common side ВС.
Then the ratio of their areas is equal to the ratio of their heights.
Svos / Svsd = KL / KO = 5 * X / 9 * X = 5/9.
9 * Svos = 5 * Svsd.
Svsd = Svsd – Ssod = Svsd – 1. (multiply by 5)
5 * Svos = 5 * Svsd – 5.
5 * Swax = 9 * Swax – 5.
4 * Swax = 5.
Swax = 5/4 = 1.25 cm2.
Answer: The area of the VOC triangle is 1.25 cm2.