In trapezoid ABCD, sin of angle A = √21 divided by 5, find the cosine of angle B.

The sum of the angles at the side of the trapezoid is 180, then CosABS = Cos (180 – BAD) = -CosBAD.

Let’s define CosBAD.

Cos2BAD = 1 – Sin2BAD = 1 – 21/25 = 4/25.

CosBAD = 2/5.

Then CosABS = – CosBAD = -2/5 = -0.4.

Answer: The cosine of angle B is equal to – 0.4.



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