In trapezoid ABCD, the diagonal AC bisects angle A and AC = AD. Find the angle D if the angle is BAC = 42 degrees?

According to the condition, AC divides the angle BAD in half, then AC is the bisector, and the angle BAC = CAD = 42.

Also, n condition, the bisector AC is equal in length to the larger base AD, therefore, the triangle ACD is isosceles, then its angles at the base CD are equal, the angle ACD = ADC.

The sum of the angles of a triangle is 180, then:

CAD + ACD + ADC = 180.

42 + 2 * ADC = 180.

ADC = (180 – 42) / 2 = 69.

Answer: Angle D = 69.



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