In trapezoid ABCD, the lower base and height are 7 and 8, find its area if the area of the triangle ABC = 60cm

The height of CH is the height of the trapezoid and the triangle BCD, then Sacd = CD * CH / 2 = 7 * 8/2 = 28 cm2.

Then Savs = Savs + Sasd = 60 + 28 = 88 cm2.

Answer: The area of the trapezoid is 88 cm2.



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