In trapezoid ABCD, the smaller base CD and the height are 7 cm and 8 cm

In trapezoid ABCD, the smaller base CD and the height are 7 cm and 8 cm, respectively. Find the area of the trapezoid if the area of triangle ABC is 60 cm2.

The height of the CH trapezoid is also the height of the triangle ABC, then:

Savs = AB * CH / 2.

AB = 2 * Savs / CH = 2 * 60/8 = 15 cm.

Then the area of the trapezoid will be equal to: Savsd = (CD + AB) * CH / 2 = (7 + 15) * 8/2 = 88 cm2.

Answer: The area of the trapezoid is 88 cm2.



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