In trapezoid ABCD, we know that AB = CD, BDA = 24, and BDC = 70. Find the angle ABD.

Since AB = CD by the problem statement, therefore, the trapezoid ABCD is isosceles.

This means that the base angles BAD and CDA are equal.

Angle CDA = BDA + BDC = 24º + 70º = 94º.

BAD = CDA = 94º.

From triangle ABD, angle ABD = 180º – (BDA + BAD) = 180º – (24º + 94º) = 180º – 118º = 62º.



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