In trapezoids ABCD it is known that AB = CD angle BDA = 30 degrees and angle BDC = 110 degrees. Find angle ABC.

Determine the value of the angle ADC.

Angle ADC = BDA + BDC = 30 + 110 = 140.

The sum of the angles of the trapezoid with its lateral side is 180, then the angle ВСD = 180 – АDC = 180 – 140 = 40.

Since, by condition, AB = CD, the trapezoid is isosceles, which means that its angles at the base are equal.

Then the angle ABC = BCD = 40.

Answer: The angle ABC is 40.



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