In triangle ABC, AB = 4cm AC = 7cm angle A = 30 degrees. Find: a) The area of the triangle.

In triangle ABC, AB = 4cm AC = 7cm angle A = 30 degrees. Find: a) The area of the triangle. b) the height drawn to the AB side.

Through the lengths of the two sides of the triangle ABC and the angle between them, we determine the area of the triangle ABC.

Savs = AB * AC * SinBAC / 2 = 4 * 7 * (1/2) / 2 = 7 cm2.

The area of the triangle ABC is also equal to:

Savs = AB * CH / 2.

СН = 2 * Saс / AB = 2 * 7/4 = 7/2 = 3.5 cm.

Answer: The area of the triangle is 7 cm, the height of the triangle is 3.5 cm.



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