In triangle ABC AB = 6.8 cm, BC = 3.2 cm, AC = 7.6 cm.Find the sides of triangle A1B1C1

In triangle ABC AB = 6.8 cm, BC = 3.2 cm, AC = 7.6 cm.Find the sides of triangle A1B1C1 similar to it, if its side A1B1 corresponds to side AB of the first triangle and is 3.4 cm larger than it.

By condition, A1B1 = AB + 3.4 = 6.8 + 3.4 = 10.2 cm.

Since triangles ABC and A1B1C1, by condition, are similar, the coefficient of similarity of triangles is K = AB / A1B1 = 6.8 / 10.2 = 2/3.

Then AC / A1C1 = K.

A1C1 = AC / K = 7.6 / (2/3) = 7.6 * 3/2 = 11.4 cm.

BC / B1C1 = K.

В1С1 = ВС / К = 3.2 / (2/3) = 3.2 * 3/2 = 4.8 cm.

Answer: A1B1 = 10.2 cm, A1C1 = 11.4 cm, B1C1 = 4.8 cm.



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