In triangle ABC, AB = 8, BC = 9, AC = 9. Find the area of triangle ABC

h = √ (AC ^ 2 – (AB / 2) ^ 2),

h = √ (92 – (8/2) ^ 2),

h = √ (81 – (4) ^ 2),

h = √ (81 – 16),

h = √65,

S = AB * h / 2,

S = (8 * √65) / 2,

S = 4 * √65.

Answer: S = 4 * √65.



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