In triangle ABC AB = BC, AC = 16cm, BD-median. find the distance from point A to line BD.
| August 3, 2021 | education
According to the conditions of the problem AB = BC, then the triangle is isosceles. and this means that the median BD, lowered to the AC side, is also the height, that is, the perpendicular to the AC side.
Therefore, the shortest distance from point A to the median BD will be the segment AD, which is half the base of AC:
AD = 16 cm / 2 = 8 cm.
Answer: The distance from point A to line BD is 8 cm.
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