In triangle ABC AB = BC, angle CAB = 30 degrees, AE – bisector, BE = 8cm. Find the area of triangle ABC.

the sectrix divided the side BC in half, since it is equal to 16 and equal to AB, draw a perpendicular from angle B and call it H, consider the triangle ABN, half lies opposite angle 30, which means that BH is 8, AH will be equal to √ (16 ^ 2-8 ^ 2 ) = X, and to find the area, you need 8 * 2X



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