In triangle ABC AB = BC, BD is the median, ∠ABD = 40∘. Find the angle C.

1) Since the median in the equilateral triangle ABC divides the AC side in half, the median BD is also the height in the ABC triangle.

2) Consider a triangle ABD. ∠ВDA = 90 ° and ∠ АВD = 40 °.

Find ∠АВD.

∠ BAD = 180 ° – 90 ° – 40 ° = 90 ° – 40 ° = 50 °.

2) Since the triangle ABC is equilateral, the sides AB and BC are equal, then ∠ BAC = ∠BCA.

Hence, ∠ С = ∠ А = 50 °.

Answer: ∠ С = 50 °.



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