In triangle ABC AB = BC BH-median ABC = 110 °, find ABH.

In accordance with the data from the conditions of our assignment, this triangle has two sides equal, that is, it is isosceles.

Therefore, based on the properties of isosceles, BH is not only the median, but also the bisector, that is, it divides the angle ABC in half.

Let’s calculate what the angle ABH of this triangle will be equal to when we know, in accordance with the data from the conditions of our task, that the angle ABC is 110 °:

110: 2 = 55.

Answer: The angle ABH of this triangle is 55 °.



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