In triangle ABC AC = 11, BC = √135, angle C = 90 degrees. Find the radius of the circumscribed circle of this triangle.

By the condition of the problem, a right-angled triangle is given in which both legs are known. In a right triangle, the hypotenuse is the diameter of the circumscribed circle. Accordingly, the radius is half the hypotenuse. Let’s use the Pythagorean theorem and find the radius of the circumscribed circle:
R = 1/2 * AB = 1/2 * √ (AC² + BC²) = 1/2 * √ (121 + 135) = 1/2 * √256 = 1/2 * 16 = 8 (cm).
Answer: the radius of the circumscribed circle is 8 cm.



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