In triangle ABC AC = BC, AD – height, angle BAD = 46. Find the corner C.

Since, by condition, AC = BC, the triangle is isosceles, which means the angle CBA = CAB.

Let the angle BAC = X, then the angle CAB = CBA = (46 – X).

In the ADC triangle, the angle is DCA = 180 – 90 – X = 90 – X.

Then the angle ACB = 180 – DCA = 180 – (90 – X) = 90 + X.

Then the sum of the angles of the triangle ABC is equal to: 180 = (46 – X) + (46 – X) + (90 + X).

X = 182 – 180 = 2.

Then ABC = 90 + 2 = 92.

Answer: Angle C = 92.



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