In triangle ABC AC = BC angle C = 116, find the outer angle CBD.

The triangle given by the condition is isosceles, the apex angle is known. Find the angle at the base:
∠ ABC = (180 ° – ∠ С) / 2 = 32 °.
External angle CBD and angle ABC are adjacent angles, we find the external angle:
∠CBD = 180 ° – ∠ ABC = 180 ° – 32 ° = 148 °.
The second option is how you can find the degree measure of the external angle – the sum of the internal angles that are not adjacent to it:
∠ CBD = ∠ С + ∠ А = 116 ° + 32 ° = 148 °.
Answer: The CBD external angle is 148 °.