In triangle ABC AD-bisector. Angle ADC = 108g angle B = 65g find angle c.

Let us determine the value of the angle ADB, which is the adjacent angle to the angle ADC. The sum of adjacent angles is 180, then the angle BAD = 180 – ADC = 180 – 108 = 72.

The sum of the inner angles of the triangle is 180, then in triangle ABD the angle BAD = 180 – 65 – 72 = 43. Since AD is the bisector of the angle, the angle BAC = 2 * BAD = 2 * 43 = 86.

Then the angle ACB = 180 – BAC – ABC = 180 – 86 – 65 = 29.

Answer: The ACB angle is 29.