In triangle ABC, AD is a bisector, angle C is 50 degrees, and CAD is 28 degrees. Find corner B.

Given:

Angle C = 50 °

CAD angle = 28 °

To find:

Corner B

The solution of the problem:

1. Angle CAD = 28 °, since AD is bisector, therefore angle CAB = 2 * 28 ° = 56 °.

2. In triangle ACB, the sum of three angles is 180 °, you need to subtract two known angles of triangle ACB from 180 °.

180 – 56 – 50 = 74 – corner B

Answer: Angle B – 74 °